最简单的jquery ajax在sturts中的应用
action：
public ActionForward ajaxTest() throws Exception {
try {
String val = getRequest().getParameter("val");
val = "回应：" + val;
getResponse().getOutputStream().print(val); // 放入response
} catch (Exception e) {
throw e;
}
return null; // 这里返回null
}
jsp：
<%@ page language="java" contentType="text/html; charset=gbk" pageEncoding="gbk"%>
<html>
<head>
<title>ajax测试</title>
<meta http-equiv="Content-Type" content="text/html; charset=gbk">
<link href="<%=request.getContextPath()%>/css/style.css" rel="stylesheet" type="text/css">
<script src="<%=request.getContextPath()%>/js/jquery-1.3.2.js" type="text/javascript"></script>
<script src="<%=request.getContextPath()%>/js/ajaxTest.js" type="text/javascript"></script>
<script type="text/javascript">
</script>
</head>
<body>
<form action="demo.do" method="post" id="demoForm">
ajax测试
<input type="text" id="val"/>
<input type="text" id="result"/>
<input type="button" id="btn" value="ajax"/>
</form>
</body>
</html>
js：
$(document).ready(function() {
$('#btn').bind('click', function() {
$.ajax({
url: 'demo.do?nextStep=ajaxTest',
data: {'val': $('#val').val()},
success : function(result) {
$('#result').val(result);
}
});
});
});
最后：
